Let `f(x)=(2x+7)/(9)` and `g(x)=(9x+5)/(7)` and we define `h(x)=f^(-1)(x)+g^(-1)(x)-5x`. If `(h^(-1)(x)=(ax+b)/(c))` where `c` is a prime then the value of `5a-2c-b ` is equal to

Let f(x) = x^(2) + 6x + 2 and g(x) = 9x +5 be two functions. Find (f+g)(x).

If f(x)=4x-5,g(x)=x^(2) and h(x)=(1)/(x) , then f(g(h(x))) is :

If f(x) = 7x + 9 and g(x) = 7x^(2) - 3 , then (f - g)(x) is equal to

Let f(x)= (2x)/(2x^2+5x+2) and g(x)=1/(x+1) . Find the set of real values of x for which f(x) gt g(x) .

Let f: R rarr R defined by f(x)=x^(3)+3x+1 and g is the inverse of 'f' then the value of g'(5) is equal to

Let f(x)=x^(2)-x+5,x>(1)/(2) and g(x) is its inverse function,then g'(7) equals

Let f (x) =x ^(2) +ax+3 and g (x) =x+b, where F (x) =lim _(xto oo) (f(x) +(x^(2))g (x))/(1+(x ^(2))^(n)). If F (x) is continous at x=1 and x=-1 then find the value of (a^(2) +b ^(2))