The equation of locus of a point equidistant from A(2 0) and the y -axis is/are

The equation of the locus of points equidistant from (-1-1) and (4,2) is

Find the locus of a point equidistant from the point (2,4) and the y-axis.

(1) The equation of locus of the point whose the distance from the x -axis is twice that of from the y -axis is (2) The equation of the locus of the point which moves equidistant form the coordinate axes is

The locus of a point which is equidistant from the x- axis and the y- axis is

The locus of a point which is equidistant from point (4,2) and x-axis is

Find the locus of a point which is equidistant from (1,3) and x -axis.

The equation of the locus of the point whose distance from the x-axis is twice that of from the y-axis is:

If the equation of the locus of a point equidistant from the points (a_1,b_1) and (a_2,b_2) is (a_1-a_2)x+(b_2+b_2)y+c=0 , then the value of C is