A boat starts from rest from one end of a bank of a river fowing with velocity u.The boat is steered with constant acceleration a in a direction perpendicular to the bank.If point of start is origin, direction of bank is x axis and perpendicular to bank is y axis.The equation of trajectory of the boat is y=`(2ax^(2))/(Nu^(2))` where N is an integer.The value of N is

The width of a river is 2sqrt3km .A boat is rowed in direction perpendicular to the banks of river.If the drift of the boat due to flow is 2 km ,the displacement of the boat is.

A particle starts from the origin of coordinates at time t = 0 and moves in the xy plane with a constant acceleration alpha in the y-direction. Its equation of motion is y= betax^2 . Its velocity component in the x-direction is

A river 500m wide is flowing at a rate of 4 m//s. A boat is sailing at a velocity of 10 m//s with respect to the water, in a direction perpendicular to the river. The time taken by the boat to reach the opposite bank

A particle moves in the x-y plane with constant acceleration alpha directed along the negative direction of the y-axis.the equation of the trajectory of the particle is y=ax- bx^2 , where a and b are constants. Find the velocity of the particle when it passes through the origin.

A particle starts from the origin of co-ordinates at time t=0 and moves in the xy plane with a constant acceleration alpha in the y -direction. Its equation of motion is y=betax^(2) . Its velocity component in the x -direction

A particle starts from the origin of coordinates at time t = 0 and moves in the xy plane with a constant acceleration alpha in the y-direction. Its equation of motion is y = beta x^(2) . Its velocity component in the x-directon is

An object starts from rest at the origin and moves along the x axis with a constant acceleration of 4m//s^(2) . Its average velocity as it goes from x=2 m to x=8 m is :

A river of width omega is flowing with a uniform velocity v. A boat starts moving from point P also With velocity v relative to the river. The direction of resultant velocity is always perpendicular to the line joining boat and the fixed point R. Point Q is on the opposite side of the river. P, Q and R are in a straight line. If PQ=QR=omega, find (a) the trajectory of the boat, (b) the drifting of the boat and (c) the time taken by the boat to cross the river.