Home
Class 11
MATHS
The equation ||x-1|+a|=4 can have real s...

The equation ||x-1|+a|=4 can have real solution for x if a belongs to the interval `(-oo, m]` then m is equal to

Promotional Banner

Similar Questions

Explore conceptually related problems

Statement I The equation |(x-2)+a|=4 can have four distinct real solutions for x if a belongs to the interval (-oo, 4) . Statemment II The number of point of intersection of the curve represent the solution of the equation.

The equation |x+1||x-1|=a^(2) - 2a - 3 can have real solutions for x, if a belongs to

The equation |x-2|+a|=4 can have four distinct real solutions for x if a belongs to the interval (-oo,-4)(b)(-oo,0)(4,oo)(d) none of these

Equation cos 2x+7=a(2-sin x) can have a real solution for

The equation 4sin^(2)x+4sin x+a^(2)-3=0 possesses a solution if 'a' belongs to the interval

The equation cos^(8)x+b cos^(4)x+1=0 will have a solution if b belongs to:

If the equation sin theta(sin theta + 2 cos theta )=a has a real solution then a belongs to the interval

If both the roots of the quadratic equation x^(2) - mx + 4 = 0 are real and distinct and they lie in the interval [1, 5], then m lies in the interval