It `cos(alpha+beta)=4/5,sin(alpha-beta)=5/(13)a n dalpha,beta` lie between `0a n dpi/4` , prove that `tan2alpha=(56)/(33)`

If cos(alpha+beta)=4/5, sin(alpha-beta)=5/13and alpha, beta between 0 and (pi)/(4),then tan 2 alpha=

cos(alpha-beta)=(3)/(5),sin(alpha+beta)=(5)/(13) then tan2 alpha

If cos(alpha+beta)=(4)/(5);sin(alpha-beta)=(5)/(13) and alpha,beta lie between 0&(pi)/(4) then find the value of tan2 alpha

If cos(alpha+beta)=3/5, sin(alpha-beta)=5/13 , and 0 lt alpha, beta lt pi/4 , then tan(2alpha) is equal to:

If cos(alpha+beta)=(4)/(5) and sin(alpha-beta)=(5)/(13) , where alpha lie between 0 and (pi)/(4) , then find that value of tan2alpha .

If cos(alpha+beta)=(4)/(5) and sin(alpha-beta)=(5)/(13) and alpha, beta lie between 0^(@) and 45^(@) , find the value of tan 2alpha :