If `sin^2theta=(x^2+y^2+1)/(2x)` , then `x` must be `-3` (b) `-2` (c) `1` (d) none of these

Explanation

To solve the equation given by \( \sin^2 \theta = \frac{x^2 + y^2 + 1}{2x} \), we need to analyze the constraints on the values of \( x \) and \( y \).

### Step-by-step Solution:

1. **Understand the Range of \( \sin^2 \theta \)**:
\[ \sin^2 \theta \leq 1 \]
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