[sin theta+sqrt(3)cos theta=6x-x^(2)-11,0<=],[" for "]

Solve for x and theta(0

sin theta+sqrt(3)cos theta=6y-y^(2)-11,theta in[0,4 pi],y in R holds for

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cos beta)/(sin 2 theta) is equal to:

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cot beta)/(sin 2 theta) is equal to:

If sin theta-sqrt(6)cos theta=sqrt(7)cos theta. Prove that cos theta+sqrt(6)sin theta-sqrt(7)sin theta=0

If sin theta-sqrt(6)cos theta=sqrt(7)cos theta .Prove that cos theta+sqrt(6)sin theta-sqrt(7)sin theta=0

If sin theta-sqrt(6)costheta=sqrt(7)costheta. Prove that cos theta-sqrt6 sin theta-sqrt7 sin theta=0.

If sin theta-sqrt(6)costheta=sqrt(7)costheta. Prove that cos theta+sqrt6 sin theta-sqrt7 sin theta=0.