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Show that sin^2 5^0+sin^2 10^0+sin^2 15^...

Show that `sin^2 5^0+sin^2 10^0+sin^2 15^0++sin^2 90^0=9 1/2dot`

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To show that \( \sin^2 5^\circ + \sin^2 10^\circ + \sin^2 15^\circ + \ldots + \sin^2 90^\circ = \frac{19}{2} \), we will follow these steps: ### Step 1: Write the series We start with the left-hand side (LHS): \[ \text{LHS} = \sin^2 5^\circ + \sin^2 10^\circ + \sin^2 15^\circ + \ldots + \sin^2 90^\circ \] ...
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Knowledge Check

  • The value of sin^2 5^@ + sin^2 10^@ + sin^2 15^@ + sin^2 20^@ + ... + sin^2 90^@ is:

    A
    7
    B
    8
    C
    9
    D
    `(19)/(2)`
  • Find the value of sin^(2)5^(@)+ sin^(2)10^(@)+ sin^(2)15^(@)+* * * +sin^(2)90^(@) .

    A
    8
    B
    9
    C
    `(17)/(2)`
    D
    `(19)/(2)`
  • The value of sin^(2)5^(@)+sin^(2)10^(@)+sin^(2)15^(@)+………+sin^(2)90^(@) is

    A
    `8 1/2`
    B
    `9 1/2`
    C
    `10 1/2`
    D
    `11 1/2`
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