Show that `sin^2 5^0+sin^2 10^0+sin^2 15^0++sin^2 90^0=9 1/2dot`

Explanation

To show that \( \sin^2 5^\circ + \sin^2 10^\circ + \sin^2 15^\circ + \ldots + \sin^2 90^\circ = \frac{19}{2} \), we will follow these steps:

### Step 1: Write the series
We start with the left-hand side (LHS):
\[ \text{LHS} = \sin^2 5^\circ + \sin^2 10^\circ + \sin^2 15^\circ + \ldots + \sin^2 90^\circ \]

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