Solve `(sin^3x/2-cos^3x/2)/(2+sinx)=(cosx)/3`

(sinx+2cos x)/(3 sinx+4cosx)

Solve 2 sin^(3) x=cos x .

Solve sin 3x + cos 2 x =-2

If sinx - cosx = 0, then the value of (sin^3 x-cos^3 x) is: यदि sinx - cosx = 0 ,तो (sin^3 x-cos^3 x) मान होगा :

Find the sum to n terms of the series (sinx)/(cosx+cos2x)+(sin2x)/(cosx+cos4x)+(sin3x)/(cosx+cos6x)+…

Solve the eqution sin^3x-cos^3x=1+1/2sin2x.

Evaluate : int(sinx-cosx)/(3+2sin2x)dx .

int_(0)^((pi)/2)(cos^(3)x)/(sinx+cosx)dx

int(sin^3x+cos^3x)/(sin^2xcos^2x)dx (A) sinx+cosx+c (B) tanx+cotx+c (C) secx-cosecx+c (D) sinx-cosx+c

Solve: cos3x+cosx-cos2x=0