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" (1) "[bx+ay=2ab],[ax-by=a^(2)-b^(2)]...

" (1) "[bx+ay=2ab],[ax-by=a^(2)-b^(2)]

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Solve the following system of equations bx + ay = 2ab and ax - by = a^(2) - b^(2) .

(ax+by)^(2)-(ay+bx)^(2)

2 (ax+by)^(2)-(bx+ay)^(2)

Solve for x and y: ax+by=1" and "bx+ay=(2ab)/(a^(2)+b^(2)) .

(ax+by)^(2)+(bx-ay)^(2)

If ax+by=1 and bx+ay=(2ab)/(a^(2)+b^(2)) then (x^(2)+y^(2))(a^(2)+b^(2)) is equal to

Solve the following simultaneous linear equations in two linear variables by the method of cross-multiplication : ax+by=1, bx+ay=(2ab)/(a^(2)+b^(2))

Solve the following system of equations in x and yax+by=1bx+ay=((a+b)^(2))/(a^(2)+b^(2))-1 or,bx+ay=(2ab)/(a^(2)+b^(2))