" 25."m-((m-1))/(2)=1-((m-2))/(3)

(m-1)/(m-4)=(2m-3)/(3m-8)

Find the value of m m - ( ( m -1 ) /2) = 1 - ( ( m - 2 ) /3)

If l : m = 2 (1)/(2) : 1(2)/(3) and m : n = 1 (1)/(4) : 3 (1)/(2) , find l : m : n

[If m_(1) and m_(2) are slopes of tangents to the hyperbola (x^(2))/(25)-(y^(2))/(16)=1 which pass through the point (6,2) then (11m_(1)m_(2))/(10)=

Show that the distance between (1,1) and ((2m^(2))/(1+m^(2)) , ((1-m)^(2))/(1+m^(2))) is independent of m.

In triangle ABC m_(1),m_(2),m_(3) are the lenghts of the medians through A,B and C respectively . If C=(pi)/(2) , then (m_(1)^(2)+m_(2)^(2))/(m_(3)^(2)) =

The value of (1-(1)/(2))(1-(1)/(3))(1-(1)/(4))(1-(1)/(m)) is (1-(1)/(2))(1-(1)/(2m) (d) (1)/(123(m-1)m)

m(m-1)(m-2)...3.2.1=

The lines y=m_(1)x,y=m_(2)xandy=m_(3)x make equal intercepts on the line x+y=1 Then (a) 2(1+m_(1))(1+m_(3))=(1+m_(2))(2+m_(1)+m_(3))(1+m_(1))(1+m_(3))=(1+m_(2))(1+m_(1)+m_(3))(1+m_(1))(1+m_(2))=(1+m_(3))(2+m_(1)+m_(3))(1+m_(1))(1+m_(3))=(1+m_(2))(1+m_(1)+m_(3))2(1+m_(1))(1+m_(3))=(1+m_(2))(1+m_(1)+m_(3))