`sum_(n=1)^ootan(theta/(2^n))/(2^(n-1)cos(theta/(2^(n-1))))`

f_(n)(theta)=sum_(n=1)^(n)tan((theta)/(2^(n)))sec((theta)/(2^(n-1))), then compute the value of f_(4)((4 pi)/(3))

sum_ (n = 1) ^ (oo) (tan ((theta) / (2 ^ (n)))) / (2 ^ (n-1) cos ((theta) / (2 ^ (n-1)) ))

If (sin^(4)theta)/(a)+(cos^(4)theta)/(b)=(1)/(a+b), prove that (sin^(8)theta)/(a^(3))+(cos^(4)theta)/(b^(3))=(1)/((a+b)^(3))(sin^(4n)theta)/(a^(2n-1))+(cos^(4n)theta)/(b^(2n-1))=(1)/((a+b)^(2n-1)),n in N

If n is a positive integer,prove the following (1+cos theta+i sin theta)+(1+cos theta-i sin theta)^(n)=2^(n+1)cos^(n)((theta)/(2))cos((n theta)/(2))

The sum sum _(n=1)^ootan^(-1)(1/(2^n+2^(1-n))) equals

Maximum value of sum_(n=1)^(3)(cos^(2n)theta+(-1)^(n+1)sin^(2n)theta),AA theta in R in R

(cos3 theta)/(2cos2 theta-1)=(1)/(2) if (n in1)