The area of a trapezium is half the product of its height and sum of parallel sides.

The area of a trapezium is half the product of its height and the sum of parallel sides.GIVEN : A trapezium ABCD in which AB|CD;AB=a,DC=b and AL=CM=h, where AL perp DC and CM perp AB. TO PROVE : ar (trap.ABCD)=(1)/(2)HX(A+B) construction : Join AC^(2)

The area of a trapezium is half the product of its height and the sum of parallel sides. GIVEN : A trapezium A B C D in which A B || C D ; A B=a ,D C=b and A L=C M=h , where A L_|_D C and C M_|_A B . TO PROVE : a r(t r a p. A B C D)=1/2h(a+b) construction : Join A C

The symbolic form of "area (A) of a trapezium is half of the product of distance between the paralel side (h) and sum of the lengths of parallel sides (a,b)" is____.

The ratio of the length of the parallel sides of a trapezium is 3:2. The shortest distance between them is 20 cm. If the area of the trapezium is 550 cm^2, the sum of the lengths of the parallel sides is-

Prove that the area of a trapezium is half the sum of the parallel sides multiplied by the distance between them.

Prove that the area of a trapezium is half the sum of the parallel sides multiplied by the distance between them.

Prove that the area of a trapezium is half the sum of the parallel sides multiplied by the distance between them.

The area of a trapezium is 279 sq. cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.