[" If the median "AD" of "Delta ABC" be perpendicular to side "AB" then "],[tan A+2tan B=0]

The median AD of a Delta ABC is perpendicular to AB,prove that tan A+2tan B=0

If the median of a triangle ABC through A is perpendicular to AB then (tan A)/(tan B) has the value equal to

If the median of a triangle ABC through A is perpendicular to AB then (tan A)/(tan B) has the value equal to

If the median of a triangle ABC through A is perpendicular to AB then (tan A)/(tan B) has the value equal to 1) (1)/(2) 2 2 3 -2 4) -(1)/(2)

In Delta ABC, if the median AD drawn through A is perpendicular to the side AC, then 3ca cos A cos C + 2a^(2) =

If the medium AD is perpendicular to the side AB in the triangle ABC, show that tan A+ 2 tan B=0 .

In a triangle ABC ,if the median AD through A is perpendicular to AB ,then AD is equal to (A) c tan B B) -ctanA (c) 2c tan A (D) -(c/2)tan A

In a DeltaABC, if median AD is perpendicular to AB, the tan A+2 tan B is equal to

In a DeltaABC, if median AD is perpendicular to AB, the tan A+2 tan B is equal to