If `H` is the othrocenter of an acute angled triangle ABC whose circumcircle is `x^2+y^2=16 ,` then circumdiameter of the triangle HBC is 1 (b) 2 (c) 4 (d) 8

Explanation

With the given details, we can create a diagram.

Please refer to video for the diagram.

Here, circumradius of `Delta ABC` = `sqrt16 = 4`

`:. a = 2*4sinA =>a = 8sinA->(1)`

Let `R_1` is the circumradius of the `Delta HBC`.

Then,

`a = 2R_1sin/_BHC`

`=2R_1sin(B+C)`

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