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If x=secvarphi-tanvarphia n dy=cos e cva...

If `x=secvarphi-tanvarphia n dy=cos e cvarphi+cotvarphi,` then `x=(y+1)/(y-1)` (b) `x=(y-1)/(y+1)` `y=(1+x)/(1-x)` (d) `x y+x-y+1=0`

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