Range of `f(theta)=cos^2theta(cos^2theta+1)+2sin^2theta` is

Range of f(theta)=cos^2theta(cos^2theta+1)+2 sin^2theta is

The range of f(theta)=3cos^(2)theta-8sqrt(3)cos theta sin theta+5sin^(2)theta-7 is gven by

cos theta+sin theta=cos2 theta+sin2 theta

Taking theta=30^(@) , verify each of the following (i) sin 2theta=2sin theta cos theta (ii) cos theta=2cos^(2)theta-1=1-2sin^(2)theta (iii) tan2theta=(2tantheta)/(1-tan^(2)theta)

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

The value of (2(sin2 theta+2cos^(2)theta-1))/(cos theta-sin theta-cos3 theta+sin3 theta)=

The range of sin^(2)theta+cos^(4)theta=A is

Prove the following identities: 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+1=0sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1(sin^(8)theta-cos^(8)theta)=(sin^(2)theta-cos^(2)theta)(1-2sin^(2)theta cos^(2)theta)

If f(theta)=|[cos^(2)theta,cos theta sin theta,-sin theta],[cos theta sin theta,sin^(2)theta,cos theta],[sin theta,-cos theta,0]| , then f((pi)/(12))

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] "then " f (pi/7) is