Figure depicts the motion of a particle moving along an x axis with a constant acceleration. What are the magnitude and direction of the particle's acceleration ? 8 6 4 2 0 2 3 t(s) -2

Figure 2-19 depicts the motion of a particle moving along an x axis with a constant acceleration. The figure's vertical scaling is set by x_(s)=6.0m . What are the (a) magnitude and (b) direction of the particle's acceleration ?

The displacement of a particle moving along x-axis is given by : x = a + bt + ct^2 The acceleration of the particle is.

At t = 0 , the particle is at the origin and its velocity is 10 m//s at an angle 37^(@) with the x-axis. The particle moves in x-y plane with a constant acceleration of 1 m//s^(2) along the y-axis. Find the magnitude and direction of the velocity after 2 s .

If the velocity of a paraticle moving along x-axis is given as v=(4t^(2)+3t=1)m//s then acceleration of the particle at t=1sec is :

The position (x) of a particle moving along x - axis veries with time (t) as shown in figure. The average acceleration of particle in time interval t = 0 to t = 8 s is

v_(x) is the velocity of a particle moving along the x-axis as shown in the figure. If x=2.0m at t=1.0s, what is the position of the particle at t=6.0s ?

The position of a particle moving along x-axis given by x=(-2t^(3)-3t^(2)+5)m . The acceleration of particle at the instant its velocity becomes zero is

Figure gives the x-t plot of a particle is one dimensional motion. Give the signs of position, velocity and acceleration of the particle at t = 0.3s

A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration. What is the magnitude of this acceleration, if the kinetic energy of the particle becomes equal to 8xx10^(-4) J by the end of the second revolution after the beginning of the motion?

If the velocity of the a particle moving on x-axis is given by v=3t^(2)-12 t +6. at what time is the acceleration of particle zero ?