A parallel plate capacitor having plate area `A` and separation between the plates `d` is charged to potential `V `.The energy stored in capacitor is ....???

A parallel plate capacitor has area of each plate A , the separation between the plates is d . It is charged to a potential V and then disconnected from the battery. The amount of work done in the filling the capacitor Completely with a dielectric constant k is.

A pararllel plate capacitor has plates of area A and separation d and is charged to potential diference V . The charging battery is then disconnected and the plates are pulle apart until their separation is 2d . What is the work required to separate the plates?

A parallel plate capacitor has plate of area A and separation d .It is charged to a potential difference V_(0) . The charging battery is disconnected and the plates are pulled apart to three times the initial separation.The work required to separate the plates is.

A parallel plate capacitor having a plate separation of 2mm is charged by connecting it to a 300v supply. The energy density is

A parallel -plate capacitor having plate area 25.0 cm^ and a separation 2.00 mm between the plates .the capacitor is connected to a bettery of 12.0 V.(a)find the charge on the capacitor .(b) the plate separation is decrerased to 1.00 mm. Find the extra charge given by the bettery to the positive plate.

A parallel plate capacitor has plates with area A and separation d. A battery charges the plates to a potential difference V_(0) . The battery is then disconnected and a dielectric slab of thikness d is introduced. The ratio of the enrgy stored in the capacitor before and after the slab is introduced, is

A parallel plate capacitor has plate A and separation d between the plates. The capacitor is connected to a battery of emf V . (a) find the charge on the capacitor. (b) the plate separation is decreases to d//2 . Find the extra charge given by the battery to the positive plate. (c) work done in reducing separation between plates.

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

The plates of a parallel plate capacitor have an area of 100cm^(2) each and area separated by 2.5 mm. the capacitor is charged to 200V. Calculate the energy stored in the capacitor.

The force between the plates of a parallel plate capacitor of capacitance C and distance of separation of the plates d with a potential difference V between the plates, is.