Home
Class 11
PHYSICS
A particle of mass m moves in xy plane s...

A particle of mass m moves in xy plane such that its position vector, as a function of time, is given by `vec(r) =b(kt-sinkt)hati+b(kt+cos kt) hatj`. where b and k are positive constants. (a) Find the time `t_0` in the interval `o le t le (pi)/k` when the resultant force acting on the particle has zero power. (b) Find the work done by the resultant force acting on the particle in the interval `t_(o) le t le (pi)/4`

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves on the xy-pane such that its position vector is given by vec(r)=3t^(2) hati-t^(3) hatj . The equation of trajectory of the particle is given by

A particle moves in xy plane with its position vector changing with time (t) as vec(r) = (sin t) hati + (cos t) hatj ( in meter) Find the tangential acceleration of the particle as a function of time. Describe the path of the particle.

Velocity-time graph of a particle moving in a straight line is shown in the figure. Mass of the particle is 2 kg. Work done by all the forces acting on the particle in time interval t = 0 to t = 10 sec is

The velocity-time graph of a particle moving in a straight line is shown in figure. The mass of the particle is 2kg . Work done by all the forces acting on the particle in time interval between t=0 to t=10s is

A particle moves in the xy plane under the influence of a force such that its linear momentum is vecP(t) = A [haticos(kt)-hatjsin(kt)] , where A and k are constants. The angle between the force and momentum is

A particle moves in the x-y plane under is influence of a force such that its linear momentum is vec(P)(t)=A[hat(i)cos (kt)-hat(j)sin (kt)] , where A and k are constants Angle between the force and the momentum is:

The position vector of a particle is given by vec(r ) = k cos omega hat(i) + k sin omega hat(j) = x hat(i) + yhat(j) , where k and omega are constants and t time. Find the angle between the position vector and the velocity vector. Also determine the trajectory of the particle.

A particle moves in the XY-plane according to the law x = kt, y = kt (1- alphat) , where k and alpha are positive constants and t is time. The trajectory of the particle is

A particle moves in the X-Y plane under the influence of a force such that its linear momentum is oversetrarrp(t)=A[haticos(kt)-hatjsin(kt)] , where A and k are constants. The angle between the force and the momentum is