If the orthogonal trajectories of the family of curves `e^(n-1)x=y^(n)` .(where e is a parameter) always passes through `(1, e)` and `(0, 0)` then value of n is

Find the orthogonal trajectories of family of curves x^(2)+y^(2)=cx

Orthogonal trajectories of the family of curves x^2 + y^2 = c^2

The orthogonal trajectories of the circle x^(2)+y^(2)-ay=0 , (where a is a parameter), is

Orthogonal trajectories of the family of curves x^(2)+y^(2)=a is an arbitrary constant is

The equation of the trajectories which is orthogonal to the family of curves cos y=ae^(-x) is

The equation of the trajectories which is orthogonal to the family of curves cos y=ae^(-x) is.

The orthogonal trajectories of the family of curves an a^(n-1)y=x^(n) are given by (A)x^(n)+n^(2)y= constan t(B)ny^(2)+x^(2)=constan t(C)n^(2)x+y^(n)=constan t(D)y=x

The orthogonal trajectories of the curves (x^(2))/(a^(2)+lambda)+(y^(2))/(b^(2)+lambda)=1 , lambda being the parameter of the family is

If the curve satisfy the equation (e^(x)+1)ydy=(y+1)e^(x)dx, passes through (0,0) and (k,1) then k is