`cos m theta=sin n theta` then `theta=`

cos m theta-sin n theta=0

5. sin m theta=sin n theta

If m and n are positive integers satisfying 1+cos2 theta+cos4 theta+cos6 theta+cos8 theta+cos10 theta=(cos m theta*sin n theta)/(sin theta) then (m+n) is equal to

If A=[[cos theta,sin theta-sin theta,cos theta]] then prove that A^(n)=[[cos n theta,sin n theta-sin n theta,cos n theta]],n in N

If(cos theta+i sin theta)(cos2 theta+i sin2 theta).....(cos n theta+i sin n theta)=1 then the value of theta is:

If cos ec theta-sin theta=m and sec theta-cos theta,=n, eliminate theta

if cos ec theta-sin theta=m and sec theta-cos theta=n, eliminate theta

IfA=[[cos theta,sin theta-sin theta,cos theta]], then lim_(x>oo)(1)/(n)A^(n) is

[[ Simplify :cos thetacos theta,sin theta-sin theta,cos theta]]+sin theta[[sin theta,-cos thetacos theta,sin theta]]