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In Delta A B C , if cotA+cotB+cotC=0 th...

In `Delta` ` A B C ,` if `cotA+cotB+cotC=0` then find the value of `cosAcos BcosC`

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To solve the problem, we need to find the value of \( \cos A \cos B \cos C \) given that \( \cot A + \cot B + \cot C = 0 \). ### Step-by-step Solution: 1. **Understanding the Condition**: We start with the condition given in the problem: \[ \cot A + \cot B + \cot C = 0 ...
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Knowledge Check

  • If ((cotAcotB-1))/((cotB+cotA))=x then the value of x is

    A
    cot(A-B)
    B
    tan (A+B)
    C
    cot(A+B)
    D
    tan(A-B)
  • In a Delta ABC , if b + c = 3a, then the value of cotB/2cotC/2, is

    A
    1
    B
    2
    C
    `sqrt3`
    D
    3
  • If tan A-tanB=x and cotB-cotA=y , then the value of cot(A-B) is

    A
    `(x-y)/(xy)`
    B
    `(1)/(x^(2))+(1)/(y^(2))`
    C
    `(x+y)/(xy)`
    D
    `xy`
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