Given `A=sin^2theta+cos^4theta,` then for all real `theta,` (a)`1lt=Alt=2` (b) `3/4lt=Alt=1` (c)`(13)/(16)lt=Alt=1` (d) `3/4lt=Alt=(13)/(16)`

Explanation

To solve the problem, we need to analyze the expression given by \( A = \sin^2 \theta + \cos^4 \theta \).

### Step-by-Step Solution:

1. **Rewrite \( \cos^4 \theta \)**:
We can express \( \cos^4 \theta \) in terms of \( \sin^2 \theta \):
\[
\cos^4 \theta = (\cos^2 \theta)^2 = (1 - \sin^2 \theta)^2
...