If `cos(A-B)=3/5a n dt a n At a n B=2,` then `cos Acos B=1/5` (b) `sin A sin B=-2/5` `cos AcosB=-1/5` (d) `sin A sinB=-1/5`

If cos(A-B)=(3)/(5) and tan A tan B=2,thencos A cos B=(1)/(5) b.cot cos B=-(1)/(5)cs in As in B=-(1)/(5)ds in As in B=-(1)/(5)

cot A cot B=2,cos(A+B)=(3)/(5)rArr sin A sin B=

a.cos A + b.cos B + c.cos C = 2a sin B sin C

([((cos A+cos B)/(sin A-sin B))^(n)+((sin A+sin B)/(cos A-cos B))^(n) when n is odd,is -

If A+B=pi/3a n d cos A+cos B=1, t h e n- a.cos(A-B)=1//3 b. |cos A-cos B| =sqrt(2/3) c.cos(A-B)= -1/3 d. |cos A-cos B|=1/(2sqrt(3))

If cos(A-B)=(5)/(13) and sin(A+B)=(4)/(5) , then find sin2B.

cos A + cos B + cos C = 1 + 4sin ((A) / (2)) sin ((B) / (2)) sin ((C) / (2))

Show that (1+sin A)/(cos A)+(cos B)/(1-sin B)=(2sin A-2sin B)/(sin(A-B)+cos A-cos B)