The base `B C` of ` A B C` is fixed and the vertex `A` moves, satisfying the condition `cotB/2+cotC/2=2cotA/2,` then `b+c=a` `b+c=2a` vertex `A` moves along a straight line Vertex `A` moves along an ellipse

The base BC of DeltaABC is fixed and the vertex A moves, satisfying the condition cot.(B)/(2) + cot.(C)/(2) = 2 cot.(A)/(2) , then

In a triangle ABC with fixed base BC,the verte moves such that cos B+cos C=4sin^(2)((A)/(2)) then

Base BC of triangle ABC is fixed and opposite vertex A moves in such a way that tan.(B)/(2)tan.(C)/(2) is constant. Prove that locus of vertex A is ellipse.

In DeltaABC , if b+c=3a , then prove that: cotB/2.cotC/2=2

In a Delta ABC , if b + c = 3a, then the value of cotB/2cotC/2, is

The base AB of a triangle is fixed and its vertex C moves such that sin A =k sin B (kne1) . Show that the locus of C is a circle whose centre lies on the line AB and whose radius is equal to (ak)/((1-k^2)) , a being the length of the base AB.

In Delta ABC, vertex B and C are fixed and vertex A is variable such that 2sin((B-C)/(2))=cos((A)/(2)) then locus of vertex A is

In a triangle ABC with fixed base BC, the vertex A moves such that cos B+cosC=4sin^(2)A/2 . If a,b,c denote the lengths of the triangle opposite to the angles A,B and C respectively, then

If A+B+C=pi and A, B, C are acute positive angles and cotA cotB cotC = k, then

In a triangle ABC with fixed base BC, the vertex A moves such that cos B + cos C = 4 sin^(2) A//2 If a, b and c denote the lengths of the sides of the triangle opposite to the angles A,B and C respectively, then