If `x = 5 + 2 sqrt(6)`, then `sqrt(x/2) - 1/(sqrt(2x)` = (a) 1 (b) 2 (c) 3 (d) 4

If x=5+2sqrt(6), then sqrt(x)-(1)/(sqrt(x)) is a.2sqrt(2)b2sqrt(3)c*sqrt(3)+sqrt(2)d*sqrt(3)-sqrt(2)

The value of x=sqrt(2+sqrt(2+sqrt(2+...))) is (a) -1 (b) 1 (c) 2 (d) 3

If x = 5+2sqrt6 , then the value of (sqrtx +frac(1)(sqrtx)) is (A) 2sqrt2 (B) 3sqrt2 (C ) 2sqrt3 (D) 3sqrt3

If x=5+2sqrt(6), then (x-1)/(sqrt(x)) is equal to a.sqrt(2) b.sqrt(3)c.2sqrt(2)d.2sqrt(3)

If x=sqrt(5)+\ 2, then x-1/x equals (a) 2sqrt(5) (b) 4 (c) 2 (d) sqrt(5)

If x=sqrt(5)+2, then x-(1)/(x) equals 2sqrt(5)(b)4 (c) 2 (d) sqrt(5)

Differentiate the following function : (i) (x^(2) - 5x + 6)(x-3) , (ii) (sqrt(x) + 1/(sqrt(x)))^(2) , (iii) (3x^(2) + 2x + 5)/(sqrt(x))

If "x=sqrt(5)+2",then "x-(1)/(x)" equals: (a) "4," (b) "3," (c) "2," (d) "1"

The value of ("lim")_(xvec2)(sqrt(1+sqrt(2+x))-sqrt(3))/(x-2)i s (a) 1/(8sqrt(3)) (b) 1/(4sqrt(3)) (c) 0 (d) none of these

The value of ("lim")_(xto2)(sqrt(1+sqrt(2+x))-sqrt(3))/(x-2)i s (a) 1/(8sqrt(3)) (b) 1/(4sqrt(3)) (c) 0 (d) none of these