If `3sinx+4cosa x=7` has at least one solution, then find the possible values of `adot`

(i)If 3sin x+4cos ax=7 has atleast one solution; find the possible values of a.(ii) Solve cos^(50)x-sin^(50)=1( iii) Solve cos4 theta+sin5 theta=2

" If "tan^(2)x+sec x=a+1" has at least one solution,then the complete set of values of "a" is "

If the equation x^(2)+4+3sin(ax+b)-2x=0 has at least one real solution, where a,b in [0,2pi] then one possible value of (a+b) can be equal to

|x+7|=3 then possible value of x is

|x+7|=3 then possible value of x is

If the equation cot^(4)x-2cos ec^(2)x+a^(2)=0 has at least one solution,then the sum of all possible integral values of a is equal to a.4b .3c.2d.0

If the equation cot^(4)x-2cos ec^(2)x+a^(2)=0 has at least one solution,then the sum of all possible integral values of a is equal to

If a, b ∈ [0,2pi] and the equation x^(2) + 4+3sin(ax+b)=2x has atleast one solution, and the least (+ve) . Value of a+b is k then,

Let f(x)=2+x, x>=0 and f(x)=4-x , x < 0 if f(f(x)) =k has at least one solution, then smallest value of k is