Prove that `(cos(90^0+theta)sec(-theta)"tan"(180^0-theta))/(sec(360^0-theta)sin(180^0+theta)cot(90^0-theta))=-1`

Explanation

To prove the given expression:

\[ \frac{\cos(90^\circ + \theta) \sec(-\theta) \tan(180^\circ - \theta)}{\sec(360^\circ - \theta) \sin(180^\circ + \theta) \cot(90^\circ - \theta)} = -1 \]

we will simplify the left-hand side (LHS) step by step.

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