Let coordinates of point P be `(4, 5)`. If `A and B` are variable points on straight lines `x = y and 2x - y =0` respectively, then the minimum value of `PA + PB + AB` is

Let coordinates of the points A and B are (5, 0 ) and (0, 7) respectively. P and Q are the variable points lying on the x- and y-axis respectively so that PQ is always perpendicular to the line AB. Then locus of the point of intersection of BP and AQ is

Let coordinates of the points A and B are (5,0) and (0,7) respectively. P and Q the variable point lying on the x-axis and y-axis respectively so that PQ is always perpendicular to the line AB. The locus of the point of intersection BP and AQ is

P is a point lying on line y = x then maximum value of |PA - PB| , (where A-=(1, 3), B-=(5, 2) ) is

P is a point lying on line y = x then maximum value of |PA - PB| , (where A-=(1, 3), B-=(5, 2) ) is

The coordinates of the point Q symmetric to the point P(–5, 13) with respect to the line 2x – 3y – 3 = 0 are -

Slope of the line AB is (-4)/(3) coordinates of points A and B are (x,-5) and (-5,3) respectively. What is the value of x?

P is the point (-1,2), a variable line through P cuts the x & y axes at A&B respectively Q is the point on AB such that PA, PQ, PB are H.P. Find the locus of Q

If A (3,1) and B (-5,7) are any two given points, If P is a point one the line y = x such that PA + PB is minimum then P is