यदि `a/(1-2a)+b/(1-2b)+c/(1-2c)=1/2`, हो तो `1/(1-2a)+1/(1-2b)+1/(1-2c)` का मान क्या है?

Options

A. 1
B. 2
C. 3
D. 4

Answer

D

Explanation

`a/(1-2a)+b/(1-2b)+c/(1-2c)=1/2`
Multiply by 2 both side
`implies (2a)/(1-2a)+(2a)/(1-2b)+(2c)/(1-2c)=1`
Adding 3 both side
`implies 1+(2a)/(1-2a)+1+(2b)/(1-2b)+1`
`(2c)/(1-2c)=1+3`
`implies 1/(1-2a)+1/(1-2b)+1/(1-2b)=4`