यदि `a^(2)+b^(2)+c^(2)=16, x^(2)+y^(2)+z^(2)=25` और `ax+by+cz=20` हो तो `(a+b+c)/(x+y+z)` का मान निकालें ?

Options

A. `3//5`\
B. `4//5`
C. `5//3`
D. `5//4`

Answer

B

Explanation

`a^(2)+b^(2)+c^(2)=x^(2)+y^(2)+z^(2)=25`
but `b=c=0` but `y=z=0`
`a=4, x=5`
Now,
`ax+by+cz=20`
`4xx5+0+0=0`
`20=20` (satisfy)
Now `(a+b+c)/(x+y+z)=(4+0+0)/(5+0+0)=4/5`