The number of solutions of the equation `tanx+secx=2cosx` lying in the interval `[0,2pi]` is 0 (b) 1 (c) 2 (d) 3

Explanation

To find the number of solutions of the equation \( \tan x + \sec x = 2 \cos x \) in the interval \([0, 2\pi]\), we can follow these steps:

### Step 1: Rewrite the equation in terms of sine and cosine
The given equation is:
\[ \tan x + \sec x = 2 \cos x \]
We can express \(\tan x\) and \(\sec x\) in terms of sine and cosine:
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