Find the area bounded by the curve `y = sin x` between `x = 0` and `x=2pi`.

Explanation

To find the area bounded by the curve \( y = \sin x \) between \( x = 0 \) and \( x = 2\pi \), we can follow these steps:

### Step 1: Understand the Function and Its Graph
The function \( y = \sin x \) oscillates between -1 and 1. It completes one full cycle from \( 0 \) to \( 2\pi \). The graph of \( \sin x \) starts at \( (0, 0) \), reaches its maximum at \( \left(\frac{\pi}{2}, 1\right) \), returns to \( ( \pi, 0) \), reaches its minimum at \( \left(\frac{3\pi}{2}, -1\right) \), and finally returns to \( (2\pi, 0) \).

### Step 2: Identify the Areas Above and Below the X-axis
From \( x = 0 \) to \( x = \pi \), the sine function is above the x-axis, and from \( x = \pi \) to \( x = 2\pi \), it is below the x-axis. Since we are interested in the area, we will take the absolute values of the areas.

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