If `cot^3alpha+cot^2alpha+cotalpha=1` then (a) `cos2alpha.tanalpha=-1` (b)`cos2alpha.tanalpha=1` (c) `cos2alpha-tan2alpha=1` (d)`cos2alpha-tan2alpha=-1`

For alpha=pi/7 which of the following hold(s) good? (a) tanalphatan2alphatan3alpha=tan3alpha-tan2alpha-tanalpha (b)cos e calpha=cos e c2alpha+cos e c4alpha (c)cosalpha-cos2alpha+cos3alpha=1/2 (d)8cosalphacos2alphacos4alpha=1

(x tan alpha+y cot alpha)(x cot alpha+y tan alpha)-4xy cos^(2)2 alpha=

If tan alpha+cotalpha=2 , then tan^(20)alpha+cot^(20)alpha =

(tan alpha sec^(2)alpha+cot alpha cos ec^(2)alpha)-(tan alpha+cot alpha)=2cos ec2 alpha[sec^(2)alpha+cos ec^(2)alpha-3]

If cot alpha cot beta=2 show that (cos(alpha+beta))/(cos(alpha-beta))=1/3

tan^(2)alpha=1-p^(2) then sec alpha+tan^(3)alpha*cos ec alpha

If cot alpha+tan alpha=m and (1)/(cos alpha)-cos alpha=n, then

If sinalpha+cos alpha=sqrt2 cos alpha then prove that tan 2alpha=1

(1)/(tan3 alpha-tan alpha)-(1)/(cot3 alpha-cot alpha)=cot2 alpha

cot^(2)alpha=1+a^(2) then cos ec alpha+cot^(3)alpha sec alpha=