`x^4+y^4-x^2y^2=`

If x = a +1/a and y=a-1/a then sqrt(x^4+ y^4-2x^2y^2) is equal to : यदि x = a +1/a और y=a-1/a है, तो sqrt(x^4+ y^4-2x^2y^2) का मान किसके बराबर होगा?

If x = a + frac(1)(a) and y = a - frac(1)(a) then find the value of x^4 +y^4 - 2x^2y^2

If x= frac(a)(b) + frac(b)(a) and y = frac(a)(b) - frac(b)(a) then show that x^4+y^4 - 2x^2y^2 = 16

Let us factorise the following. (x^4y^2 - 4x^2y^2)

Subtract x^3y^2+3x^2y^3-7xy^3 " from " x^4+y^4+3x^2y^2-xy^3 .

If x=sqrtp+1/sqrtp and y=sqrtp-1/sqrtp , then find the value x^(4)+y^(4) -2x^2y^2

if x^(4) -y^(4)-x^(2)y^(2)-2xy^(3)= z^(6) then prove that log_(z)(x^(2) -y^(2)-xy) + log_(z) (x^(2) +y^(2) +xy) =6

Factorise : x^(4) + y^(4) - 2x^(2)y^(2)