2m^(3)-13m^(2)+22m-8

If m is a real number such that m^(2)+1=3m the value of (2m^(5)-5m^(4)+2m^(3)-8m^(2))/(1+m^(2))

Solve the following quadratic equations by factorisation method. (i) x^(2) +8x+15=0 (ii) 5m^(2) - 22m - 15= 0

Simplify the following: 10m^(2) - 9m + 7m - 3m^(2) - 5m -8

Add :5m(3-m) and 6m^(2)-13m4y(3y^(2)+5y-7) and 2(y^(3)-4y^(2)+5)

Add (i)5m(3-m) and 6m^(2)-13m-13m (ii) 4y(3y^(2)+5y-7) and 2(y^(3)-4y^(2)+5)

Divide: m^3-14 m^2+37 m-26\ b y\ m^2-12 m+13 x^4+x^2+1\ b y\ x^2+x+1

Solve for m: (m-3)/(2) + (m-2)/(3) = -13