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" (vi) "[(1)/(4)a-(1)/(2)b+1]^(2)...

" (vi) "[(1)/(4)a-(1)/(2)b+1]^(2)

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Expand each of the following using suitable identities : [(1)/(4)a-(1)/(2)b+1]^(2)

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The factors of 8a^(3)+b^(3)-6ab+1 are (a) (2a+b-1)(4a^(2)+b^(2)+1-3ab-2a) (b) (2a-b+1)(4a^(2)+b^(2)-4ab+1-2a+b)(2a+b+1)(4a^(2)+b^(2)+1-2ab-b-2a) (d) (2a-1+b)(4a^(2)+1-4a-b-2ab)

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(7)/(2^((1)/(2))+2^((1)/(4))+1)=A+B*2^((1)/(4))+C.2^((1)/(2))+D.2^((3)/(4))