[3x-3y=8],[6x-y=(29)/(3)]

4x-3y=8, 6x-y=29/3

Solve the following equations by Elimination method : 4x-3y=8, 6x-y=29/3 .

4x+3y=4,6x+5y=8

3x+2y=8 2x-3y=8

4x-2y=3 6x-3y=5

6x-4y=-12,8x-3y=-2

2x+3y=8 4x-5y=-6

The equation of the normal to the curve 3x^2-y^2=8 which is parallel to x+3y=8 is x-3y=8 (b) x-3y+8=0 (c) x+3y+-8=0 (d) x+3y=0

6x-3y=-10,3x+5y-8=0

Solve: 6x - 3y = 13, 2x + y =3