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[" A untorin ang positive "x-a],[" direc...

[" A untorin ang positive "x-a],[" direction alonero at "x=0],[" potential "V" is zero "],[" will be: "]

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A uniform field of 8 N/C exists in space in positive x-direction. (a) Taking the potential at the origin to be zero, write an expression for the potential at a general point (x, y, z). (b) At which points, the potential is 160 V ? (c) It the potential at the origin is taken to be 80V, what will be the expression for the potential at a general point ? (d) What will be the potential at the origin if the potential at x = infinity is taken to be zero ?

A uniform field of 8 N/C exists in space in positive x-direction. (a) Taking the potential at the origin to be zero, write an expression for the potential at a general point (x, y, z). (b) At which points, the potential is 160 V ? (c) It the potential at the origin is taken to be 80V, what will be the expression for the potential at a general point ? (d) What will be the potential at the origin if the potential at x = infinity is taken to be zero ?

Let there be a uniform electric field "E" existing along the positive X-direction.Assume electric potential to be zero at the origin.Potential at the point x=x_(0) is

A unifrom electric field having a magnitude E_(0) and direction along the positive X-axis exists. If the protential V is zero at x = 0 , then its value at X = +x will be

A unifrom electric field having a magnitude E_(0) and direction along the positive X-axis exists. If the protential V is zero at x = 0 , then its value at X = +x will be

The potential energy ‘V’ of a particle moving along the positive x-direction in a conservative force field varies as shown in the figure. The total energy is E=2. Draw the corresponding kinetic energy K vs x graph.

The potential energy ‘V’ of a particle moving along the positive x-direction in a conservative force field varies as shown in the figure. The total energy is E=2. Draw the corresponding kinetic energy K vs x graph.

The position vector vecr of a particle points along the positive direction of a z axis. If the torque on the particle is (a) zero, (b) in the negative direction of x, and ( c) in the negative direction of y, in what direction is the force causing the torque?