समीकरण `tan 2theta = "tan"(2)/(theta)` को हल कीजिए |

Explanation

`tan 2theta = "tan" (2)/(theta)= tan (n pi+(2)/(theta))`
`rArr " " 2theta = n pi +(2)/(theta)`
`rArr " " 2theta^(2)-n pi theta - 2 = 0`
अतः `" " theta = (n pi pm sqrt(n^(2)pi^(2)+16))/(4)`
`rArr " " theta =(n pi)/(4) pm sqrt(1+(n^(2)pi^(2))/(16))`, जहाँ `n in I`.