The upper `3/4` th portion of a vertical pole subtends an angle `theta` such that tan `theta=3/5` at a point in the horizontal plane through its foot and at a distance 40m from the foot. Find the possible height of the vertical pole.

Explanation

Let `h` is the height of the vertical pole.

It is given that , `tan theta = 3/5`

We can draw a diagram wuth the given details.

Please refer to video for the diagram.

From the diagram,

`beta = alpha+theta`

`=>tan beta = tan(alpha+theta)`

`=>h/(CD) = (tanalpha+tantheta)/(1-tanalphatantheta)`

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