A relation `R` is defined from `A` to `B` by `R={(x, y)}, \ "where" \ x in NN, y in NN, and x+y=4}`. Then, `R` is (A) symmetric (B) reflexive (C) equivalence (D) both (A) and (B)

9. A relation R is defined from A to B byR= {(x, y)}, where xe N, YE N, and x+y=4}. Tlien, R is (a) symmetric (b) reflexive (c) equivalence (d) both (a) and (b)

If R={(x,y):x in NN, y in NN and 2x+y=10} , then R^-1=?

Domain of the relation R = {(x,y) : x in NN,. Y in NN and 2x+y=41} is-

A relation R is defined on the set of natural numbers N as follows: R={(x,y)}|x,y in N and 2x+y=41} show that R is neither reflexive nor symmetric nor transitive.

If R be a relation in a set A and (x, y) in R rArr(y, x) in R AA x, y in A then the relation R is called (A) reflexive (B) symmetric (C) transitive (D) equivalence

If a relation R on the set N of natural numbers is defined as (x,y)hArrx^(2)-4xy+3y^(2)=0 , where x,y inN . Then the relation R is (a) symmetric (b) reflexive (c) transitive (d) an equivalence relation.

If R={(x,y):x inNN,y in NN and x+2y=8} , then the number of elements of R will be____

A relation R is defined on the set of natural numbers NN follows : (x,y) in R implies x+y =12 for all x,y in NN Prove that R is symmetric but neither reflexive nor transitive on NN .

6.In the set A={1,2,3,4,5), a relation R is defined by R={(x,y):x, ye Aand rlty }. Then R is (a) reflexive (b) symmetric (c) transitive (d) none of these

A relation R is defined on the set of natural numbers NN as follows : R {(x,y) : x in NN and x is a multiple of y }. Prove that R is reflexive, antisymmetric and transitive but not symmetric on NN .