In the expansion of `(x+a)` ,sum of the odd terms is `P` and the sum of even terms is `Q` then `4PQ`.

In the expansion of (x+a)^(n) if the sum of odd terms is P and the sum of even terms is Q then (a)P^(2)-Q^(2)=(x^(2)-a^(2))^(n)(b)4PQ=(x+a)^(2n)-(x-a)^(2n)(c)2(P^(2)+Q^(2))=(x+a)^(2n)+(x-a)^(2n) (d)none of these

In the expansion of (x + a)^(n) the sum of even terms is E and that of odd terms is O, then OE is equal to

In the expansion of (x +a)^(n) the sum of even terms is E and that of odd terms is O, them O^(2) + E^(2) is equal to

If there are (2n+1) terms in A.P.then prove that the ratio of the sum of odd terms and the sum of even terms is (n+1):n

The number of terms of an A.P.is even; the sum of the odd terms is 310; the sum of the even terms is 340 ; the last term exceeds the first by 57. Find the number of terms and the first terms of series.

The number of terms of an A.P. is odd. The sum of the odd terms (1 ^(st), 3 ^(rd) etc,) is 248 and the sum of the even terms is 217. The last term exceeds the first by 56 then :

The number of terms of an A.P.is even; the sum of the odd terms is 24, and of the even terms is 30 ,and the last term exceeds the first by 10/2 then the number of terms in the series is 8 b.4 c.6 d.10