`A(3,-4)` is a vertex of `Delta ABC` and `3x+4y-18=0` is the perpendicular bisector of the side `AB` .If `C=(6,3)` then the centroid of the triangle is

If a vertex of a triangle is (1, 1) and the mid-points of two side through this vertex are (-1, 2) and (3, 2), then centroid of the triangle is

The equations of the perpendicular bisectors of the sides AB&AC of a triangle ABC are x-y+5=0&x+2y=0. find the equation of the bc

If the middle points of the sides of a triangle be (- 2, 3), (4, - 3) and (4, 5), then the centroid of the triangle is:

Points A(3,5) , B (-1,4) and C( 7,-6) are the vertices of Delta ABC. Find the coordinates of the centroid of the triangle

Let ABC be a triangle and A -= (1,2) ,y = x be the perpendicular bisector of AB and x-2y+1=0 be the perpendicular bisector of angle C . If the equation of BC is given by ax+by-5 = 0 then the value of a -2b is

If the middle points of the sides of a triangle are (-2,3),(4,-3), and (4,5), then find the centroid of the triangle.

In triangle ABC, the coordinates of the vertex A are , (4,-1) and lines x - y - 1 = 0 and 2x - y = 3 are the internal bisectors of angles B and C . Then the radius of the circles of triangle AbC is