How much steam at `100^(0)C` is to be passed into water of mass `100g` at `20^(0)C` to raise its temperature by `5^(0)C`? (latent heat of steam is `540cal/gm`)

50 g of steam at 100^@ C is passed into 250 g of at 0^@ C . Find the resultant temperature (if latent heat of steam is 540 cal//g , latent heat of ice is 80 cal//g and specific heat of water is 1 cal//g -.^@ C ).

A thermally insulated pot has 150 g ice at temperature 0^(@)C . How much steam of 100^(@) C has to be mixed to it , so that water of temperature 50^(@)C will be obtained ? ( Given : Latent heat of melting of ice = 80 cal/g, latent of vaporization of water = 540 cal/g, spcific heat of water = 1 cal// g.^(@)C)

20 g of steam at 100^@ C is passes into 100 g of ice at 0^@C . Find the resultant temperature if latent heat if steam is 540 cal//g ,latent heat of ice is 80 cal//g and specific heat of water is 1 cal//g^@C .

Steam is passes into 22 g of water at 20^@C . The mass of water that will be present when the water acquires a temperature of 90^@C (Latent heat of steam is 540 cal//g ) is

A thermally insulated pot has 200 g ice at temperature 0^(@)C . How much steam of 100^(@)C has to be mixed to it, so that water of temperature 40^(@)C will be obtained? (Given: Latent heat of melting of ice = 80 cal/g, latent heat of vaporisation of water = 540 cal/g, specific heat of water = I " cal/g " ^(@)C)

Steam is passed into 54 gm of water at 30^(@)C till the temperature of mixture becomes 90^(@)C . If the latent heat of steam is 536 cal//gm , the mass of the mixture will be

The water of mass 75 g at 100^(@)C is added to ice of mass 20 g at -15^(@)C . What is the resulting temperature. Latent heat of ice = 80 cal//g and specific heat of ice = 0.5 .