`logx-1/2log(x-1/2)=log(x+1/2)-1/2log(x+1/8)`

log x-(1)/(2)log(x-(1)/(2))=log(x+(1)/(2))-(1)/(2)log(x+(1)/(8))

log(x-1)+log(x-2)lt log(x+2)

log(x+1)^(x^(2))=4log(x+1)

Solve log(x+1)=2logx

log_(2)(x^(2)-1)=log_((1)/(2))(x-1)

int(log_e(x+1)-log_ex)/(x(x+1))dx is equal to (A) -1/2[log(x+1)^2-1/2logx]^2+log_e(x+1)log_ex+C (B) -[(log_e(x+1)-log_ex]^2 (C) c-1/2(log(1+1/x))^2 (D) none of these

log_(10)x-(1)/(2)log_(10)(x-(1)/(2))=log_(10)(x+(1)/(2))-(1)/(2)log_(10)(x+(1)/(8))

Solve for x:|log^(2)(4-x)+log(4-x)*log(x+(1)/(2))-2log^(2)(x+(1)/(2))=

int(dx)/(x(x^(2)+1)) equal (A) log|x|-(1)/(2)log(x^(2)+1)+Clog|x|+(1)/(2)log(x^(2)+1)+Cquad -log|x|+(1)/(2)log(x^(2)+1)+Cquad (1)/(2)log|x|+log(x^(2)+1)+C

If log_(1//2)(4-x)gelog_(1//2)2-log_(1//2)(x-1) ,then x belongs to