If `(1-i)(1-2i)(1-3i)…..(1-ni)=x-iy` , then `2.5.10 ……(1+n^2)=`

If quad (1-i)(1-2i)(1-3i)...(1-ni)=x-iy then 2.5*10...(1+x)^(2)=...

If (1+i)(1+2i)(1+3i)(1+ni)=(x+iy), show tht 2.5.10(1+n^(2))=x^(2)+y^(2)

If (1+i)(1+2i)(1+3i)...(1+ni)=a+ib then 2xx5xx10xx...(1+n^(2))=

If (1+i)(1+2i)(1+3i)(1+ni)=a+ib then 2.5.10.17(1+n^(2))=a-ibba^(2)-b^(2)c*a^(2)+b^(2)d none of these

If (1+i)(1+2i)(1+3i)......(1+ni)=a+ib,then2xx5xx10...(1+n^(2)) is equal to sqrt(a^(2)+b^(2))(b)sqrt(a^(2)-b^(2))(c)a^(2)+b^(2)(d)a^(2)-b^(2)(e)a+b

(i+(2)/(i))((1-i)/(1+i))=x+iy

If ((1+i)/(1-i))^(2)=x+iy, find x+y