Home
Class 12
PHYSICS
The closed distance of approach of an al...

The closed distance of approach of an `alpha-` particle travelling with velocity V towards a stationary nucleus is `d`.For the closest distance to become `(d)/(3)` towards a stationary nucleus of double of the charge,the velocity of projection of the `alpha-` particle has to be

Promotional Banner

Similar Questions

Explore conceptually related problems

A closest distance of approach of an "alpha" particle travelling with a velocity "v towards "Al(13)" nucleus is d The closest distance of approach of an alpha particle travelling with velocity 4V towards Fe(26) nucleus is

A closest distance of approach of an a particle travelling with a velocity V towards Al_(13) nucleus . d . The closest distacne of approach of an alpha particle travelling with velocity 4V toward Fr_(26) nucleus is

A 5 MeV alpha particle is projected towards a stationary nucleus of atomic number 40. Calculate distance of closest approach.

When an alpha particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze, its distance of closest approach form the nucleus depends on m as

An alpha -particle with kinetic energy K is heading towards a stationary nucleus of atomic number Z . Find the distance of the closest approach.

When an alpha- particle of mass 'm' moving with velocity 'v' bombards on a heavy nucleus of charge 'Ze' its distance of closest approach from the nucleus depends on m as :

Calculate the nearest distance of approach of an alpha -particle of energy 2.5 Me V being scattered by a gold nucleus (Z=79).