A particle moves according to the equation `t=sqrt(x)+3`, when will be the particle come to the rest for the first time

A particle moves according to the equation t = ax^(2)+bx , then the retardation of the particle when x = (b)/(a) is

A particle moves according to the equation x= a cos pi t . The distance covered by it in 2.5 s is

A particle oscillates, according to the equation x = 5 cos (pit//2) m. Then the particle moves from equilibrium position to the position of maximum displacement in time of

A particle moves according to the law x=t^(3)-6t^(2)+9t+5 . The displacement of the particle at the time when its acceleration is zero, is

A particle is oscillating according to the equation x = 8 cos pi t , where 't' is in second. The particle moves from the position of equilibrium to maximum displacement in time

A particle is oscillating according to the equation x = 10cos2pit , where 't' is in seconds. The particle moves from the position of maximum displacement to equilibrium in time.

Consider a particle moving in simple harmonic motion according to the equation x=2.0cos(50pit+tan^-10.75) where x is in centimetre and t in second. The motion is started at t=0. a. When does the particle come to rest for the first time? B. When does the acceleration have its maximum magnitude for the first time? c. When does the particle comes to rest for the second time?

A particle moves according to equation x = A cos pi t . The distance covered by it in 3.5 s is

A particle moves in x-y plane according to the equation bar(r ) = (hat(i) + 2 hat(j)) A cos omega t the motion of the particle is

A particle move along y-axis according to equation y +3+4 cos omega t . The motion of the particle is